Boundary value problems.

The simplest case is that of boundary value problems where NDIM=NBC and where NINT=0. Then, generically, one free problem parameter is required for computing a solution family. For example, in demo exp, we have NDIM=NBC=2, NINT=0. Thus NICP=1. Indeed, in this demo one free parameter is designated, namely PAR(1).

More generally, for boundary value problems with integral constraints, the generic number of free parameters is NBC + NINT$-$NDIM +1. For example, in demo lin, we have NDIM=2, NBC=2, and NINT=1. Thus NICP=2. Indeed, in this demo two free parameters are designated, namely PAR(1) and PAR(3).