A shell script interprets a number
as decimal (base 10), unless that number has a
special prefix or notation. A number preceded by a
` 0` is

**Example 8-4. Representation of numerical constants**

#!/bin/bash # numbers.sh: Representation of numbers in different bases. # Decimal: the default let "dec = 32" echo "decimal number = $dec" # 32 # Nothing out of the ordinary here. # Octal: numbers preceded by '0' (zero) let "oct = 032" echo "octal number = $oct" # 26 # Expresses result in decimal. # --------- ------ -- ------- # Hexadecimal: numbers preceded by '0x' or '0X' let "hex = 0x32" echo "hexadecimal number = $hex" # 50 # Expresses result in decimal. # Other bases: BASE#NUMBER # BASE between 2 and 64. # NUMBER must use symbols within the BASE range, see below. let "bin = 2#111100111001101" echo "binary number = $bin" # 31181 let "b32 = 32#77" echo "base-32 number = $b32" # 231 let "b64 = 64#@_" echo "base-64 number = $b64" # 4094 # # This notation only works for a limited range (2 - 64) # 10 digits + 26 lowercase characters + 26 uppercase characters + @ + _ echo echo $((36#zz)) $((2#10101010)) $((16#AF16)) $((53#1aA)) # 1295 170 44822 3375 # Important note: # -------------- # Using a digit out of range of the specified base notation #+ will give an error message. let "bad_oct = 081" # numbers.sh: let: oct = 081: value too great for base (error token is "081") # Octal numbers use only digits in the range 0 - 7. exit 0 # Thanks, Rich Bartell and Stephane Chazelas, for clarification. |